Linux/Unix 主机中安装的一个或多个程序包受到一个漏洞影响，而供应商没有提供补丁程序。

  - 已修复 Linux 内核中的下列漏洞：net: enetc: avoid deadlock in enetc_tx_onestep_tstamp() This lockdep splat says it better than I could: ================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted
    -------------------------------- inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at:
    netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811):
    [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20 other info that might help us debug this: Possible unsafe locking scenario: CPU0 ---- lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2); *** DEADLOCK *** 3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at:
    process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2:
    ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34 Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0
    __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel. To solve this, use netif_tx_lock_bh(), which blocks softirqs from running. (CVE-2023-53022)

请注意，Nessus 依赖供应商报告的程序包是否存在进行判断。

Linux/Unix 主機上安裝了一個或多個受到弱點影響的套件，且供應商未提供可用的修補程式。

  - 已解決 Linux 核心中的下列弱點：net: enetc: avoid deadlock in enetc_tx_onestep_tstamp() This lockdep splat says it better than I could: ================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted
    -------------------------------- inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at:
    netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811):
    [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20 other info that might help us debug this: Possible unsafe locking scenario: CPU0 ---- lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2); *** DEADLOCK *** 3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at:
    process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2:
    ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34 Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0
    __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel. To solve this, use netif_tx_lock_bh(), which blocks softirqs from running. (CVE-2023-53022)

請注意，Nessus 依賴供應商報告的套件存在。

Linux/Unix ホストには、ベンダーが提供するパッチが利用できない脆弱性の影響を受ける複数のパッケージがインストールされています。

  - Linux カーネルでは、以下の脆弱性が解決されています: net: enetc: avoid deadlock in enetc_tx_onestep_tstamp() This lockdep splat says it better than I could: ================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted
    -------------------------------- inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at:
    netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811):
    [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20 other info that might help us debug this: Possible unsafe locking scenario: CPU0 ---- lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2); *** DEADLOCK *** 3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at:
    process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2:
    ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34 Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0
    __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel. To solve this, use netif_tx_lock_bh(), which blocks softirqs from running. (CVE-2023-53022)

Nessus は、ベンダーによって報告されたパッケージの存在に依存していることに注意してください。

The Linux/Unix host has one or more packages installed that are impacted by a vulnerability without a vendor supplied patch available.

  - In the Linux kernel, the following vulnerability has been resolved: net: enetc: avoid deadlock in     enetc_tx_onestep_tstamp() This lockdep splat says it better than I could: ================================     WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted
    -------------------------------- inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179     [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at:
    netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0     sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c     ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c     addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c     run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c     do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64     irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130     hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at     (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811):
    [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20 other info that might help us debug this: Possible unsafe     locking scenario: CPU0 ---- lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2); *** DEADLOCK *** 3 locks     held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at:
    process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8     ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2:
    ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34 Workqueue: events     enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0
    __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0     netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100     process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c but I'll say it anyway: the     enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it     can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the     NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the     kernel. To solve this, use netif_tx_lock_bh(), which blocks softirqs from running. (CVE-2023-53022)

Note that Nessus relies on the presence of the package as reported by the vendor.

ID	Name	Product	Family	Published	Updated	Severity
249931	Linux Distros 未修补的漏洞：CVE-2023-53022	Nessus	Misc.	8/15/2025	11/12/2026	medium
249931	Linux Distros 未修補弱點：CVE-2023-53022	Nessus	Misc.	8/15/2025	11/12/2026	medium
249931	Linux Distros のパッチ未適用の脆弱性: CVE-2023-53022	Nessus	Misc.	8/15/2025	11/12/2026	medium
249931	Linux Distros Unpatched Vulnerability : CVE-2023-53022	Nessus	Misc.	8/15/2025	11/12/2026	medium

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